Calculate Percentage of Nitrogen in Urea (H2NCONH2) | N Proportion Homework

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SUMMARY

The percentage of nitrogen in urea (H2NCONH2) is calculated to be 46.66%. This is derived using the formula %N = [(molar mass of nitrogen)(number of nitrogen atoms in the molecule)] / (molar mass of the molecule). The molar mass of nitrogen is 28 g/mol, and the total molar mass of urea is 60 g/mol. Both the direct calculation and the rearranged equation yield the same result, confirming the accuracy of the method.

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Homework Statement



Calculate the percentage of nitrogen in urea (H2NCONH2).


Homework Equations





The Attempt at a Solution


I tried and found %N = 46.66%
 
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That's the answer I get too. % N = [(molar mass N)(# N atoms in molecule)]/(molar mass of molecule)
 
i got it by this law: 28/N% = 60/100%
therefore: N% = (28 X 100) / (60)
 
Equally valid. If you rearrange your equation (or mine), you'll see that they are equivalent.

I like to show units, though, because it offers a good "check" if I need it and can keeps me from getting confused.
 

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