Calculate Percentage Purity by Mass of C10H7OH Contaminated with LiBr

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The discussion focuses on calculating the percentage purity by mass of a C10H7OH sample contaminated with LiBr. The combustion analysis revealed 77.48% carbon and 5.20% hydrogen, leading to the conclusion that the remaining mass percentage is attributed to oxygen and LiBr. To determine the percentage purity, one must subtract the mass of LiBr from the total sample mass, with the formula indicating that the remaining elements can be calculated based on the known composition of C10H7OH.

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A sample of C10H7OH was found to be contaminated with a small amount of LiBr. The combustion analysis of the sample gave the following results: 77.48% C and 5.20% H. Assume that the only species present are C10H7OH and LiBr, calculate the percentage purity by mass of the sample.

First of all, what is the percentage of purity by mass...? And second, does it mean that 100%-77.48%-5.20% gives the percentage of O and LiBr?
 
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physicsss said:
First of all, what is the percentage of purity by mass...? And second, does it mean that 100%-77.48%-5.20% gives the percentage of O and LiBr?
If you had 100g of the sample and found that it contained x grams of LiBr, then the percentage purity would be 100-x.

From the formula of the compound, can you not determine how much O there is in it ?
 

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