Calculate pH of 0.5 L Solution of 0.300 M HCL & 0.400 M HIO3

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SUMMARY

The pH of a solution prepared by mixing 50.0 mL of 0.300 M HCl with 450.0 mL of 0.400 M HIO3 is calculated to be 0.714. The calculation involves determining the new molarity of each acid after mixing, followed by applying the ICE (Initial, Change, Equilibrium) method to find the hydrogen ion concentration. The dissociation constant (Ka) for HIO3 is 1.6 x 10^-1, which influences the pH calculation. The final pH value is rounded to two significant digits due to the precision of the given Ka.

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  • Understanding of acid-base chemistry, specifically strong and weak acids.
  • Knowledge of the ICE method for equilibrium calculations.
  • Familiarity with pH calculations and molarity concepts.
  • Basic skills in performing dilution calculations.
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Homework Statement



What is the pH of a solution prepared by mixing 50.0 mL of 0.300 M HCL with 450.0 mL of 0.400 M HIO3? HIO3 Ka = 1.6 x 10^-1

Homework Equations



ICE

The Attempt at a Solution



I first converted each concentration to its new molarity by figuring out the number of moles of each then dividing by the new volume of 0.5 L. I used the ICE method to determine the H+ concentration. I got a pH of 0.714.
 
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0.714 looks OK :smile:

Although it should be more like 0.71, you are given only 2 significant digits of Ka.


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