1. The problem statement, all variables and given/known data Just a general question to see if i'm doing this right. The volume just doesn't seem right. Anyways we have a water supply of 1.6 million gallons with a pH of 9.93. We want to get the water to a pH of 6 using a 30% HCl solution. 2. Relevant equations M1V1+M2V2=M3V3 M1=9.93pH or 10-9.93 V1=1.6 million gallons or 6056656 liters M2=pH of 30% HCl or molarity of 10.2 V2=Volume of HCl (What I want to find) M3=6.00pH or 10-6 V3=V1+v2 3. The attempt at a solution I also converted into liters. I assumed a molarity of 30% HCl to be around 10.2 and I assumed that V3=V1+V2 (1.17486x10-10)(6056656 liters)+(10.2)(V2)=(1.0x10-6)(6056656+V2) Manipulating the equation to solve I ended up with a volume of approximately 0.6 liters of HCl needed to reduce the pH. It just seems like a very small amount of acid in order to handle that much water. ANY help at all is greatly appreciated.