- #1

physicsgrouch

- 9

- 0

[tex]\tau[/tex] = F[tex]\bot[/tex]*r

I know that there is no rotation of the drywall, and it is a thin, rectangular plate. The lever arm of the leading builder is (L/2) * cos(15). The torque of this builder is thus 123*cos(15)*(1/2)*(L/2) = 184 N*m.

This means that the torque of the other builder must be the same. However, I can't figure out what the lever arm of this other builder is; is it the same as the leader? It looks like the corners produce different lever arms at an angle, but I'm not sure how to prove that. I thought that the lever arm would be shorter by a distance of W*sin(15), but this is wrong. What am I missing?