Calculate Takeoff Speed and Jump Length Increase for Long Jump

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Homework Help Overview

The discussion revolves around a physics problem related to projectile motion, specifically focusing on the long jump scenario where an athlete takes off at a specific angle and distance. The original poster seeks to determine the takeoff speed and the effect of a speed increase on jump length.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need for the original poster to demonstrate their understanding of the equations of motion relevant to projectile motion. There are inquiries about specific variables used in the equations, such as the initial velocity.

Discussion Status

The conversation is ongoing, with some participants emphasizing the importance of showing attempts and understanding rather than seeking direct answers. Guidance has been offered regarding the separation of horizontal and vertical components of motion, but no consensus has been reached on the specific approach to solving the problem.

Contextual Notes

Participants note that the original poster's request for a solution without showing their work does not align with the forum's guidelines for homework help. There is also mention of the need to consider the effects of gravity and the assumption of no horizontal acceleration in the context of the problem.

txbigrich
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Easy But Dont Get!

An athlete executing a long jump leaves the ground at a 32.7 angle and travels 7.71m .

A) What was the takeoff speed in m/s?

B) If this speed were increased by just 4.0%, how much longer would the jump be?

Can you answer this for me. And if you could add some on how you got it.

Thanks
 
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txbigrich said:
Can you answer this for me.
No, it doesn't work like that

And if you could add some on how you got it.
The idea is that you attempt it and we tell you what you did wrong.
 


I have no clue how too, that’s why I’m posting it and asking to show how it’s done. Come on, if your good at a subject like physics, then you should already know this, there genius.
 


It's not a question of if I already know it - this is a homework forum, just telling you the answer is no more use than me saying that the answer sheets are in the top left drawer of the teacher's desk.

When you posted the question it displayed instructions to show what equations you know and your attempt at a solution

There are three equations of motion in your textbook for this kind of situation.
v = u + gt, v2 = u2 + 2gs and s = ut + 1/2 g t2 The actual letters might vary.

The trick is to consider the horizontal and vertical components of the motion separately and how the speed changes in each direction.
 


What is the variable "U" stand for?
 


U is the initial velocity, v is the final velocity.

Hint - there is no horizontal accelaration, if you ignore air resistance the horizontal speed is constant. Vertical accelearation is fixed by gravity.
 

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