Solving Long Jump Question: Find Takeoff Speed

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Homework Statement



A runner jumps at 30 degrees to the ground and covers 8.90 m. What was the takeoff speed?


The Attempt at a Solution



I have no idea where to start...
 
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Resolve the velocity into vertical and horizontal components.
What happens to these components with respect to time?
 
how would i go about solving the velocity for each component?
 
If v is the velocity what are the vertical and horizontal components?
 
honestly, i have no idea
 
Open any textbook. And refer the motion in two dimension.
 
but all i have is the angle of the jump and the distance...no time or anything
 
Using proper equation you can find the remaining unknown quantities. Try to find out the equations.
 
do u mean these formulas?

Fx = cos A * F1
Fy = sin A * F1
 
  • #10
honestly, I am struggling and have no idea what to do...
 
  • #11
SirMarksAlot said:
do u mean these formulas?

Fx = cos A * F1
Fy = sin A * F1
Yes. These are the two components. Only replace F by v for the velocity.
In that x component remains constant, because there is no acceleration in that direction. If t is the time of flight, then x = vcosθ*t.
In the vertical direction, the initial velocity is vsinθ. What is the final velocity when it reaches the maximum height. And what is the time taken to reach the maximum height?
 
  • #12
when u say x = vcosθ*t , what is v? the speed before the jump?
 
Last edited:
  • #13
No. You have to find out. I have told you to write down all the kinematic equations. Then I will tell you which equation to be used to find the time.
 
  • #14
oh wouldn't the final velocity be 0 when it reaches a maximum height? because he would have stopped moving up?
 
  • #15
Yes.
 
  • #16
I don't know how to find the time it would take to reach the max height.
 
Last edited:
  • #17
Why can't you write down all the relevant kinematic equation. In the post submitted to PF, this is the second requirement.. You have not submitted that. Do it first now.
 

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