Solving Long Jump Question: Find Takeoff Speed

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Homework Help Overview

The problem involves a runner jumping at an angle of 30 degrees and covering a horizontal distance of 8.90 meters. The objective is to determine the takeoff speed of the runner.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss resolving the jump's velocity into horizontal and vertical components and question how these components relate to time. There are inquiries about the formulas for calculating these components and the implications of the jump's angle and distance.

Discussion Status

Participants are exploring various aspects of the problem, including the relationship between the components of velocity and the time of flight. Some guidance has been offered regarding the use of kinematic equations, but there is no explicit consensus on the next steps or methods to be employed.

Contextual Notes

There is a noted lack of information regarding time and other quantities, which is affecting the participants' ability to progress in solving the problem.

SirMarksAlot
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Homework Statement



A runner jumps at 30 degrees to the ground and covers 8.90 m. What was the takeoff speed?


The Attempt at a Solution



I have no idea where to start...
 
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Resolve the velocity into vertical and horizontal components.
What happens to these components with respect to time?
 
how would i go about solving the velocity for each component?
 
If v is the velocity what are the vertical and horizontal components?
 
honestly, i have no idea
 
Open any textbook. And refer the motion in two dimension.
 
but all i have is the angle of the jump and the distance...no time or anything
 
Using proper equation you can find the remaining unknown quantities. Try to find out the equations.
 
do u mean these formulas?

Fx = cos A * F1
Fy = sin A * F1
 
  • #10
honestly, I am struggling and have no idea what to do...
 
  • #11
SirMarksAlot said:
do u mean these formulas?

Fx = cos A * F1
Fy = sin A * F1
Yes. These are the two components. Only replace F by v for the velocity.
In that x component remains constant, because there is no acceleration in that direction. If t is the time of flight, then x = vcosθ*t.
In the vertical direction, the initial velocity is vsinθ. What is the final velocity when it reaches the maximum height. And what is the time taken to reach the maximum height?
 
  • #12
when u say x = vcosθ*t , what is v? the speed before the jump?
 
Last edited:
  • #13
No. You have to find out. I have told you to write down all the kinematic equations. Then I will tell you which equation to be used to find the time.
 
  • #14
oh wouldn't the final velocity be 0 when it reaches a maximum height? because he would have stopped moving up?
 
  • #15
Yes.
 
  • #16
I don't know how to find the time it would take to reach the max height.
 
Last edited:
  • #17
Why can't you write down all the relevant kinematic equation. In the post submitted to PF, this is the second requirement.. You have not submitted that. Do it first now.
 

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