Calculate the current through each ideal battery

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The discussion focuses on calculating the current through each ideal battery in a circuit with resistances R1 = 1.0 Ω, R2 = 2.0 Ω, and voltages ε1 = 4.0 V, ε2 = 8.0 V, and ε3 = 8.0 V. The user initially applies Kirchhoff's Junction and Loop rules but encounters issues with the direction of current I2. The correct approach involves ensuring consistent current direction throughout the equations, specifically by considering I2 as negative in the calculations. This adjustment leads to accurate results in the current calculations.

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1. (a) Calculate the current through each ideal battery in the figure. Assume that R1 = 1.0 Ω, R2 = 2.0 Ω, ε1 = 4.0 V, and ε2 = ε3 = 8.0 V. Take positive current as that flowing through the battery from - to +. (See diagram)




I just need some guidance about how to set this problem up.

I've tried applying the Junction rule, to give me I1 + I3 = I2

And then the Loop rule to give:

4.0 V - 1(I1) - 2(I2) - 8V - 1(I1) = 0

8V - 1(I3) - 2(I2) - 8V - 1(I3) = 0



Am I setting this problem up correctly and using the right equations?

Thanks
 

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According to the problem, you should have taken I2 in the other direction. Either replace I2 by -I2 in all equations, or replace I2 by -I2 after you're done. Apart from that it's ok.
 

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