Calculate the [H3O+] concentration (in M) in a 0.1 M aqueous solution of NH3

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SUMMARY

The discussion focuses on calculating the hydronium ion concentration ([H3O+]) in a 0.1 M aqueous solution of ammonia (NH3) using its base dissociation constant (Kb = 1.8 x 10-5). The correct concentration is determined to be 7.5 x 10-12 M. Participants clarify that the Kb value provided is specific to ammonia and not related to the ebullioscopic constant of water. The calculation involves understanding the dissociation of NH3 in water and utilizing the ICE table method for equilibrium concentrations.

PREREQUISITES
  • Understanding of weak base dissociation and equilibrium concepts
  • Familiarity with the ICE table method for calculating concentrations
  • Knowledge of Kb values and their significance in acid-base chemistry
  • Basic skills in pH calculations and hydronium ion concentration determination
NEXT STEPS
  • Learn how to construct and use ICE tables for equilibrium calculations
  • Study the relationship between Kb and pH in weak base solutions
  • Explore the concept of dissociation constants and their applications in chemistry
  • Research the effects of temperature on Kb values and their implications in aqueous solutions
USEFUL FOR

Chemistry students, educators, and anyone involved in acid-base chemistry or seeking to understand the behavior of weak bases in solution.

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Homework Statement


Calculate the [H3O+] concentration (in M) in a 0.1 M aqueous solution of NH3.
[Kb = 1.8 x 10–5 ]
(a) 7.5 x 10–12 M (c) 1.8 x 10–6 M
(b) 3.0 x 10–10 M (d) 1.3 x 10–3 M


Homework Equations


ΔTb = Kb x m


The Attempt at a Solution


So... I'm kind of at a loss here. First of all to do anything useful with the ΔTb = Kb x m equation, they would have to give ΔTb right? And also, because its an aqueous solution, I assume we are dissolving NH3 into water. The Kb of water is 0.512... why then do they give a Kb value of 1.8 x 10–5?

Thanks in advance :smile: The answer is a, btw, but why!?
 
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