Calculate the theoretical yield of a polymer (polysuccinimide)

  • Thread starter Thread starter vasschina
  • Start date Start date
  • Tags Tags
    Polymer
AI Thread Summary
To calculate the theoretical yield of polysuccinimide (PSI) synthesized from aspartic acid, begin with the balanced chemical equation for the reaction. The stoichiometry of the reaction will determine the molar ratios of aspartic acid to polysuccinimide. Given that 10g of aspartic acid was used, convert this mass to moles using its molar mass. Then, apply the stoichiometric ratios from the balanced equation to find the expected moles of PSI produced. Finally, convert the moles of PSI back to grams to determine the theoretical yield. The actual yield of 7.3g can then be compared to the theoretical yield to calculate the percentage yield of the reaction.
vasschina
Messages
1
Reaction score
3
Hello everyone,
I am trying to find how to calculate the theoretical yield of polysuccinimide I synthesized from the aspartic acid. I added 10g of Asp and i took 7,3g of PSI. Someone who knows how to find the yield?
 
Chemistry news on Phys.org
On a basic level this is a simple HS level stoichiometric question. Start with the reaction equation.
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
Back
Top