Calculate total energy from potential at equilibrium point

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Homework Help Overview

The problem involves a block connected to a spring, oscillating on a frictionless surface. Participants are discussing how to calculate the total energy of the system at the equilibrium point, given the mass, spring constant, and speed of the block at that position.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between potential and kinetic energy at the equilibrium point, questioning the presence of potential energy when the spring is unstretched. There is also discussion about the implications of the block's speed on the total energy calculation.

Discussion Status

The discussion is ongoing, with participants clarifying concepts related to potential and kinetic energy. Some have confirmed that potential energy is zero at the equilibrium point, while others are considering how this affects the total energy of the system.

Contextual Notes

Participants are navigating the implications of the problem's constraints, such as the conditions at the equilibrium point and the nature of energy conservation in oscillatory motion.

EliteCodexer
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Homework Statement


A block of mass 0.25 kg is connected to a spring with spring constant 35 N/m. The block is oscillating on a frictionless horizontal surface. Its speed as it passes through its equilibrium position is 1.04 m/s. What's the total energy of the system?2. The attempt at a solution
Not sure how to find potential energy at equilibrium point given the speed as it passes through. I really just need someone to walk me through this problem.

Total Energy=Potential+Kinetic
 
Last edited:
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At the equilibrium point, there is no net force on the block. What does that tell you about the spring potential energy at that point?
 
there is none?
 
EliteCodexer said:
there is none?
That is correct. The spring is at its original unstretched length at that point. So what is the total energy at the equilibrium point in this example?
 
what about the kinetic energy though?
 
EliteCodexer said:
what about the kinetic energy though?
The total energy of the system is constant at at any point in time and equal to the sum of the kinetic and potential energies at any point in time. The total energy of the system at the equilibrium point is thus? and thus the total energy of the system at any point is?
 

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