Calculate Work Done by Gravity: Physics Homework Problem

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Homework Help Overview

The problem involves calculating the total work done by the force of gravity on a ball thrown upwards from a height. The ball has a mass of 0.179 kg, an initial vertical speed of 10.00 m/s, and is thrown from a height of 1.94 m above the ground. The task is to determine the work done by gravity as the ball moves downward until it hits the ground.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of gravitational force and the application of work formulas. There are attempts to clarify the role of initial velocity and displacement in the context of work done by gravity. Some participants question the sign conventions used for displacement and gravitational force.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the assumptions related to sign conventions. Some guidance has been offered regarding the direction of forces and work, but no consensus has been reached on the final approach to the solution.

Contextual Notes

There is a mention of potential confusion regarding the incorporation of initial velocity into the work calculation, as well as the need to consider the signs of displacement and gravitational force. Participants are navigating through these assumptions without resolving them.

reaperkid
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Homework Statement



A 0.179 kg ball is thrown straight up from 1.94 m above the ground. Its initial vertical speed is 10.00 m/s. A short time later, it hits the ground. Calculate the total work done by the force of gravity during that time.

m = .179 kg
vi = 10m/s (upward)
g = 9.8 m/s2
d = -1.94 m (since the displacement is downward)

Homework Equations



W = Fd
F = ma

The Attempt at a Solution



This seemed like a simple problem, I'm not sure why it's giving me so much trouble. Basically, I just need to find the force of gravity which I thought was just 9.8 * .179 but I'm clearly missing something.

I tried... W = -1.94 * (9.8 * .179)

Thanks
 
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reaperkid said:

Homework Statement



A 0.179 kg ball is thrown straight up from 1.94 m above the ground. Its initial vertical speed is 10.00 m/s. A short time later, it hits the ground. Calculate the total work done by the force of gravity during that time.

m = .179 kg
vi = 10m/s (upward)
g = 9.8 m/s2
d = -1.94 m (since the displacement is downward)

Homework Equations



W = Fd
F = ma

The Attempt at a Solution



This seemed like a simple problem, I'm not sure why it's giving me so much trouble. Basically, I just need to find the force of gravity which I thought was just 9.8 * .179 but I'm clearly missing something.

I tried... W = -1.94 * (9.8 * .179)

Thanks

x_f^2=x_i^2+2ad, W=Fd\rightarrow W=mg(x_f^2-x_i^2)/2a.
 
asleight said:
x_f^2=x_i^2+2ad, W=Fd\rightarrow W=mg(x_f^2-x_i^2)/2a.

That doesn't incorporate the initial velocity though does it?

Wouldn't

xi = 1.94 m ?
xf = 0 m ?
 
Ignore asleight's nonsense.

You did almost the correct thing: you chose the displacement as negative (fine, that's just a convention), but then you should take the acceleration due to gravity as negative, too! Both are downward.

And even without thinking about sign conventions: does gravity do positive or negative net work here?
 
I seee, it's positive because it's in the direction of gravity.

Thank you very much sir! :)
 
You're welcome!
 

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