Calculate Work Done by Gravity: Physics Homework Problem

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SUMMARY

The discussion focuses on calculating the total work done by gravity on a 0.179 kg ball thrown upward with an initial speed of 10.00 m/s from a height of 1.94 m. The relevant equations include W = Fd and F = ma, where the force of gravity is calculated as F = mg. The correct approach involves recognizing that both the displacement and the acceleration due to gravity are negative, resulting in a positive net work done by gravity as it acts in the direction of the ball's displacement when it falls.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of work-energy principle (W = Fd)
  • Familiarity with gravitational acceleration (g = 9.8 m/s²)
  • Basic concepts of kinematics (displacement, initial and final velocity)
NEXT STEPS
  • Study the work-energy theorem in detail
  • Learn about kinematic equations for uniformly accelerated motion
  • Explore the concept of sign conventions in physics problems
  • Investigate the implications of positive and negative work in different contexts
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Students studying physics, particularly those tackling problems related to work and energy, as well as educators looking for examples of gravitational work calculations.

reaperkid
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Homework Statement



A 0.179 kg ball is thrown straight up from 1.94 m above the ground. Its initial vertical speed is 10.00 m/s. A short time later, it hits the ground. Calculate the total work done by the force of gravity during that time.

m = .179 kg
vi = 10m/s (upward)
g = 9.8 m/s2
d = -1.94 m (since the displacement is downward)

Homework Equations



W = Fd
F = ma

The Attempt at a Solution



This seemed like a simple problem, I'm not sure why it's giving me so much trouble. Basically, I just need to find the force of gravity which I thought was just 9.8 * .179 but I'm clearly missing something.

I tried... W = -1.94 * (9.8 * .179)

Thanks
 
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reaperkid said:

Homework Statement



A 0.179 kg ball is thrown straight up from 1.94 m above the ground. Its initial vertical speed is 10.00 m/s. A short time later, it hits the ground. Calculate the total work done by the force of gravity during that time.

m = .179 kg
vi = 10m/s (upward)
g = 9.8 m/s2
d = -1.94 m (since the displacement is downward)

Homework Equations



W = Fd
F = ma

The Attempt at a Solution



This seemed like a simple problem, I'm not sure why it's giving me so much trouble. Basically, I just need to find the force of gravity which I thought was just 9.8 * .179 but I'm clearly missing something.

I tried... W = -1.94 * (9.8 * .179)

Thanks

x_f^2=x_i^2+2ad, W=Fd\rightarrow W=mg(x_f^2-x_i^2)/2a.
 
asleight said:
x_f^2=x_i^2+2ad, W=Fd\rightarrow W=mg(x_f^2-x_i^2)/2a.

That doesn't incorporate the initial velocity though does it?

Wouldn't

xi = 1.94 m ?
xf = 0 m ?
 
Ignore asleight's nonsense.

You did almost the correct thing: you chose the displacement as negative (fine, that's just a convention), but then you should take the acceleration due to gravity as negative, too! Both are downward.

And even without thinking about sign conventions: does gravity do positive or negative net work here?
 
I seee, it's positive because it's in the direction of gravity.

Thank you very much sir! :)
 
You're welcome!
 

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