Calculate <x^2> for Hydrogen Atom Ground State | Symmetry Method

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Homework Help Overview

The problem involves calculating the expectation value for the ground state of a hydrogen atom, specifically without performing new integrations. The original poster references a symmetry that may relate this calculation to previous results from part (a) of the problem, which dealt with finding and for the same state.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of spherical symmetry on the relationship between , , and . There is exploration of whether these expectations contribute equally to and how measurements along different axes compare under spherical symmetry.

Discussion Status

Some participants have begun to understand the symmetry involved and have attempted integrals to support their reasoning. There is recognition that the integrals for , , and should yield the same results due to the spherical symmetry of the ground state, although some express uncertainty about the representation of these integrals in different coordinate systems.

Contextual Notes

Participants note that the integrals are typically evaluated in spherical coordinates, which may obscure their similarities compared to rectangular coordinates. There is an acknowledgment that the symmetry should lead to equal expectation values for the three components, but the transition between coordinate systems may not be immediately clear to all students.

YAHA
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Homework Statement


The problem (4.13 (b) in Grifitths) asks to find <x^2> of the ground state of hydrogen atom. It asks to do so without new integration. Supposedly, there is some kind of symmetry and one can use the results from part (a) of the problem. Part (a) is finding <r> and <r^2> for the same state.


Homework Equations





The Attempt at a Solution


I am failing to see the symmetry he is talking about.
 
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There is no angular dependence in the ground state. Then what can you say about the relation between
&lt;x^2&gt; , &lt;y^2&gt; and &lt;z^2&gt; ?
 
Last edited:
They add up to <r^2>, correct?
 
That's part of the answer, but that's always true no matter the symmetry of the problem. The key is in the following question: how do measurements along different axes compare when you have spherical symmetry?
 
If you can't <see> it from the physical perspective, try from the mathematical one. Write down the 3 integrals of exp values for x^2, y^2 and z^2. Then prove they are equal one to another.
 
So does this means that due to spherical symmetry, electron is equally likely to be measured along any of the 3 axis? In other words, x y z are equally likely to contribute to the final vector (r)?
 
YAHA said:
So does this means that due to spherical symmetry, electron is equally likely to be measured along any of the 3 axis? In other words, x y z are equally likely to contribute to the final vector (r)?

Not sure exactly what you mean by that. However, what you should do is set up the integrals needed to calculate <x^2>,<y^2> and <z^2>. Look for similarities between the integrals. Do they look the same or different? For example: consider the following integrals,

\int_0^5 (y+2)^2 dy

and

\int_0^5 (x+2)^2 dx

Do they have the same values when evaluated or different values?
 
Last edited:
YAHA said:
So does this means that due to spherical symmetry, electron is equally likely to be measured along any of the 3 axis? In other words, x y z are equally likely to contribute to the final vector (r)?

Yes, that's what <spherical symmetry> of the ground state means.
 
Alright I understand it now. I did the integrals also and it worked. Expectations of all components are equal. They are 1/3 of expectation of r.
 
  • #11
AlexChandler said:
Not sure exactly what you mean by that. However, what you should do is set up the integrals needed to calculate <x^2>,<y^2> and <z^2>. Look for similarities between the integrals. Do they look the same or different? For example: consider the following integrals,

\int_0^5 (y+2)^2 dy

and

\int_0^5 (x+2)^2 dx

Do they have the same values when evaluated or different values?

The problem with this analogy is that usually these integrals are evaluated in spherical coordinates, and in those coordinates, x, y and z look quite different from each other. I don't think it would be obvious to someone looking at those three integrals that they have to be the same.
 
  • #12
Right, r^2. :) Thanks for everyone's help.
 
  • #13
Steely Dan said:
The problem with this analogy is that usually these integrals are evaluated in spherical coordinates, and in those coordinates, x, y and z look quite different from each other. I don't think it would be obvious to someone looking at those three integrals that they have to be the same.

The point is that they are exactly the same integrals. It doesn't matter if you use x or y or Ω or √ or ∏ to label the variable, it is simply the same integral. It is like asking if the solutions to the following equations will be the same or different:

λ+2=1

θ+2=1

it doesn't matter which variable you use, the solution is always -1
 
  • #14
AlexChandler said:
The point is that they are exactly the same integrals. It doesn't matter if you use x or y or Ω or √ or ∏ to label the variable, it is simply the same integral. It is like asking if the solutions to the following equations will be the same or different:

λ+2=1

θ+2=1

it doesn't matter which variable you use, the solution is always -1

Yes, but your comment was to "look for similarities" in the integrals; what I took from that was the implication that since the integrals are identical in form in rectangular coordinates, one could conclude they all had the same value. But the integrals do not look identical in spherical coordinates, even though they represent the same quantity. So the idea of "looking for similarities" is only helpful insofar as the student already knows to represent the integrals in rectangular coordinates (at which point it is obvious). I simply suggested that most students do not think to make this switch in the first place, since they are taught the hydrogen atom in spherical coordinates to begin with (due to the above symmetry). Also, the symmetry relationship should be obvious (no offense intended to the OP, of course) without even having to write down the integrals -- if the ground state is spherically symmetric, then by definition no direction can be preferred. That statement alone is enough to conclude that the expectation value should be the same for any of the three variables.
 

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