Calculating Acceleration and Net Force of a Moving Block | Homework Question

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SUMMARY

The discussion focuses on calculating the acceleration and net force of an 8.0 kg block being pulled by a constant force of 2N across a rough horizontal surface. The block moves a distance of 3.0m in 6 seconds, leading to an acceleration of 0.08 m/s². The net force acting on the block is calculated using the formula Fnet = Ma, resulting in a net force of 0.64N. The incorrect application of the formula v = d/t for accelerated motion is highlighted, emphasizing the need to use the equation d = Vi*t + 0.5*a*t² for accurate calculations.

PREREQUISITES
  • Understanding of Newton's Second Law (Fnet = Ma)
  • Basic kinematics, including distance, velocity, and acceleration equations
  • Knowledge of motion on rough surfaces and the impact of friction
  • Ability to manipulate and solve algebraic equations
NEXT STEPS
  • Study kinematic equations in detail, focusing on d = Vi*t + 0.5*a*t²
  • Learn about frictional forces and their effects on net force calculations
  • Explore advanced applications of Newton's laws in real-world scenarios
  • Practice problems involving varying forces and mass to solidify understanding of acceleration
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to force and motion.

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Homework Statement


A block of mass 8.0kg starting from rest is pulled along a rough horizontal tabletop by a constant force of 2N it is found that the block moves a distance of 3.0m in 6 seconds
a) what is the acceleration?
b) What is the net force acting on the block?

Homework Equations


Fnet = Ma



The Attempt at a Solution


v = d/t
v = 3/6
v = 0.5m/s
a = v/t
a = 0.08m/s^2
Fnet = 8 x 0.08
= 0.64N [F]
 
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You can't use v = d/t when the motion is accelerated.
Use formulas with acceleration in them.
d = Vi*t + .5*a*t² should work well.
 

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