Net Force acting on block on incline

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SUMMARY

The net force acting on a 6.50 kg block on an incline of 18.8° is calculated to be zero. This conclusion is reached because the block remains at rest, indicating that the forces acting on it are balanced. The coefficients of static and kinetic friction, 0.685 and 0.485 respectively, confirm that the frictional force is sufficient to prevent motion. Therefore, the net force, calculated using the equation F = ma, results in F = 6.50 kg * 0 m/s² = 0 N.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of static and kinetic friction
  • Knowledge of trigonometric functions related to angles
  • Basic algebra for solving equations
NEXT STEPS
  • Study the effects of different angles on frictional forces
  • Learn about the calculation of forces on inclined planes
  • Explore the relationship between mass, acceleration, and net force
  • Investigate real-world applications of static and kinetic friction
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Students studying physics, particularly those focusing on mechanics and forces, as well as educators looking for examples of net force calculations on inclined surfaces.

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Homework Statement


A 6.50 kg block is placed on an inclined surface. The coefficients of static and kinetic friction between the block and the surface are 0.685 and 0.485, respectively. The incline makes an angle of 18.8° relative to horizontal. The block is at rest and remains at rest. What is the magnitude of the net force that acts on the block?

Homework Equations


net Force, F = ma

The Attempt at a Solution


F = ma
F = mass * acceleration
F = mass * 0
net Force, F=0
 
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