Calculating angles for a physical regular icosahedron

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hephalumph
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This is actually for a wood shop project... but it certainly involves geometry! I am trying to build a real-world regular icosahedron. I know I need 20 equilateral triangles for the faces. But I do not know what the angles of the sides/thickness should be, to join those 20 triangles into a 3D shape. Nor do I know how to calculate it. I'll be perfectly honest - this is not some homework or test that I *have* to figure it out for myself and show proof of work, so if someone wants to just post the answer, I am fine with that. But if you want to make me work for it, giving me the formula as a starting point, (and probably working with me to verify I solved it correctly) is okay too.

Thanks in Advance!
 
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hephalumph said:
This is actually for a wood shop project... but it certainly involves geometry! I am trying to build a real-world regular icosahedron. I know I need 20 equilateral triangles for the faces. But I do not know what the angles of the sides/thickness should be, to join those 20 triangles into a 3D shape. Nor do I know how to calculate it. I'll be perfectly honest - this is not some homework or test that I *have* to figure it out for myself and show proof of work, so if someone wants to just post the answer, I am fine with that. But if you want to make me work for it, giving me the formula as a starting point, (and probably working with me to verify I solved it correctly) is okay too.

Thanks in Advance!

Good afternoon,

have a look here: https://en.wikipedia.org/wiki/Regular_icosahedron

If I understand you correctly you are looking for the dihedral angle between two faces. You'll find the value of this angle in the table of properties of the icosahedron.
 
If you already know this, it's no help. But here's a way to construct an icosahedron:

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