Calculating Angular Velocity: Motor at 60rpm Comes to Rest in 10 Revolutions

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SUMMARY

The discussion focuses on calculating the angular velocity of a motor that starts at 60 RPM and comes to rest after 10 revolutions, with its angular velocity decreasing linearly with angular displacement. The formula for angular velocity is established as ω(θ) = ω₀ - Cθ, where ω₀ is the initial angular velocity. To find the constant C, it is noted that the angular velocity reaches zero after 10 revolutions, necessitating conversion to radians for accurate calculations. The next step involves differentiating the angular velocity function with respect to θ to relate it to the time derivative of angular velocity.

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pratz
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A motor rotating at 60rpm comes to rest in 10 revolutions with its angular velocity decreasing linearly with angular displacement.Determine it angular velocity as a function of time and determine angular velocity w at t=3 sec..


I need help with this problem...Please someone help...I can't do anything in rotational mechanics:(
 
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Hi Pratz, welcome to PF!

To get you started, you know the that the angular velocity is a linearly decreasing function of angular displacement, meaning that:

[tex]\omega(\theta) = \omega_0 - C\theta[/tex]​

You know what the inital angular velocity, [itex]\omega_0[/itex] is, because it is given in the problem. You can calculate the constant by noting that the angular velocity equals zero after ten revolutions: [itex]\omega(10 \textfm{rev}) = 0[/itex]. Remember to convert everything into radians. Now that you have this function [itex]\omega(\theta)[/itex], you can differentiate it with respect to theta. Can you think of a way of relating that to the time derivative of [itex]\omega[/itex]?
 

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