Calculating Average Speed from Lap 1 & 2

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Homework Help Overview

The discussion revolves around calculating the average speed for two laps completed at different speeds: 135 mph for lap 1 and 90 mph for lap 2. The original poster expresses confusion regarding the calculation, believing the average speed to be 112.5 mph, while the provided answer is 108 mph.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the definition of average speed and question the validity of simply averaging the two speeds. There is a discussion about the need for distance and time in the calculation, as well as the implications of equal lap lengths.

Discussion Status

Some participants have offered guidance on how to approach the problem using algebraic expressions for time and distance. There is an ongoing exploration of the correct formulas and the relationships between the variables involved, but no consensus has been reached on the final calculation.

Contextual Notes

Participants note the absence of specific distance or time values, which complicates the calculation. The assumption that the laps are of equal length is also highlighted as a critical factor in the discussion.

NettioB
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Homework Statement



Hi

I read a question recently on the British Mensa website and I thought the answer was 112.5mph. The answer given was 108mph. What is the calculation for this scenario?

"Lap 1 is completed at 135mph, lap 2 is completed at 90mph, what’s the average speed?"



Homework Equations



summation and division of two numbers


The Attempt at a Solution



135 plus 90 equals 225. 225 divided by 2 eqals 112.5


Thanks.

N.
 
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NettioB said:

Homework Equations



summation and division of two numbers
Not in this case. Averaging is sometimes tricky. Average speed is defined as total distance traveled divided by total time required to travel that distance. Use this idea and you might be surprised with the result.
 
NettioB said:
So? Can you do the calculation as I indicated? It requires a little bit of algebra or the realization that is question is entirely analogous to finding the equivalent resistance of two resistors in parallel or the equivalent capacitance of two capacitors in series.
 
With this information I cannot. We only have two average speeds, one per lap (or two constant speeds, one per lap). We have neither a distance or a time.
 
NettioB said:
We have neither a distance or a time.
Neither of these are needed. Just the knowledge that the laps are of equal length. Start writing something down and see what develops.

Step 1. Can you write an equation for the definition of the average speed that I gave you? Use symbols for quantities that you don't know and have faith that it will all come out in the wash.
 
If L = lap distance and T1 and T2 = time to travel each lap, we can write:

Average speed = 4L / (T1 + T2)

But I can't get further than this.
 
It should be

vave = 2L/(t1+t2) where L is the distance of one lap. The total trip is two laps or 2L.

Step 2: Can you find expressions for t1 and t2 in terms of L and v1 and v2?
 
t1 = v1 / L

t2 = v2 / L

Vavg = 2L2 / (v1 + v2)

= 2L2 / (135 + 90)

= L2 / 112.5


Where can I go from here?
 
  • #10
NettioB said:
t1 = v1 / L

t2 = v2 / L
No. t1 = L / v1 and t2 = L / v2.

Step 3: Now add the two times together to get the sum. Be sure to add the fractions correctly on the right side. Replace the sum t1+t2 in the equation for vave and see what you get.
 

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