Calculating Cable Angles for Suspended Beam

[3wt Man]

I have a beam suspended by two cables with two weights suspended by the beam. The weight of the beam is negligible. How would I find the resting angles of the cables.

 

[HallsofIvy]

Take T1 to be the tension in one cable, T2 the tension in the other. Take $\theta1$ to be the angle the first cable makes with the horizontal, $\theta2$ to be the angle the second cable makes. You can calculate the x and y components of both tension vectors in terms of T and $\theta$. You know what the y component of each must be- they are given. You know that the x components must cancel, because the beam does not move left or right.

 

[3wt Man]

This is not a homework problem!
It has been so long since I did anything like that.
I have
T1x=T2x
T1y+T3y+W1=0
T2y+T3y+w2=0

Then I get lost

 

[3wt Man]

Okay I worked it out again, I finally get to a point where a Angle C = something Angle A.
This needs to be in a resting position and that is where my problem is.
W1=350lbs W2=650lbs B=20Deg