Calculating Coefficients of Friction for a Moving Clock on a Horizontal Floor

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Hello, i was abscent two days of last week and this is one of the problems from the homework that I missed. My teacher didn't give me any formula and the notes he gave don't go over this so I am asking for help, thanks a lot Zach.


a 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocit. Find µs and µk between the clock and the floor.
 
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Welcome to PF!

Hi Zach! Welcome to PF! :wink:

Use friction force = µ times normal force. :smile: