Calculating Coefficient of Friction for a Crate on an Inclined Surface

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SUMMARY

The coefficient of friction for a 225 kg crate on a 20-degree inclined surface is calculated to be 0.665. A horizontal force of 535 N is required to initiate movement down the incline, indicating the presence of frictional forces opposing the motion. The calculation utilizes Newton's laws of motion to derive the necessary frictional force (Ftr) and the angle's cosine value. The discussion highlights the importance of accurate numerical input in solving physics problems.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic trigonometry, specifically cosine functions
  • Knowledge of frictional force concepts
  • Ability to perform calculations involving forces and angles
NEXT STEPS
  • Study the application of Newton's laws in real-world scenarios
  • Learn about different types of friction and their coefficients
  • Explore inclined plane problems in physics
  • Practice calculating forces using trigonometric functions
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and forces, as well as educators looking for practical examples of friction on inclined surfaces.

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Homework Statement


A 225 kg crate rests on a surface that is inclined above the horizontal at an angle of 20o.
A horizontal force (F = 535 N parallel to the ground, not the incline) is required to start the crate moving down the incline. What is the coefficient of friction between the crate and the incline?

P.S. Ftr is a frictional force.

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Homework Equations


Newton's laws of motion.

The Attempt at a Solution


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It doesn't work.
The answer must be 0.665 .[/B]
 
Physics news on Phys.org
Funny. That's exactly what I get. What is ##\cos\alpha## on your calculator ?
 
I missed one number xD. Sorry for wasting your time.
 

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