Calculating Constant Speed of a Train with Variable Acceleration

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Homework Help Overview

The problem involves a train that starts from rest, accelerates over a distance of 60 m, travels at a constant speed for 120 m, and then decelerates over 30 m, with the entire journey taking 25 seconds. The goal is to find the constant speed of the train.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to analyze each segment of the train's journey to determine the constant speed. There are mentions of writing equations for different parts of the trip, but uncertainty remains about how to proceed after establishing initial equations.

Discussion Status

The discussion is ongoing, with participants expressing confusion about the next steps after formulating initial equations. Some guidance has been offered regarding the necessity of considering all parts of the trip to find the constant speed.

Contextual Notes

Participants note that simply writing down equations is insufficient and that a more comprehensive analysis of the entire trajectory is required. There is an emphasis on the need to connect the equations for the different phases of motion.

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Homework Statement


A train is at 0 m/s at the begining. It accelerates on a distance of 60 m, after it goes on a constant speed on the next 120 m and it finally decelerates on the next on 30 m and stops. The whole traject is 25 sec. Find the constant speed.

Homework Equations



x final = x initial + v initial * t + 1/2 * a * t^2

The Attempt at a Solution



60 = 0 + 0 + 1/2* a* t^2

60 = 1/2 * a * t^2

We also know that the first traject goes from 0 to 60 m and from 60 to 180 m and finally from 180 to 210 m.
 
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astrololo said:

Homework Statement


A train is at 0 m/s at the begining. It accelerates on a distance of 60 m, after it goes on a constant speed on the next 120 m and it finally decelerates on the next on 30 m and stops. The whole traject is 25 sec. Find the constant speed.

Homework Equations



x final = x initial + v initial * t + 1/2 * a * t^2

The Attempt at a Solution



60 = 0 + 0 + 1/2* a* t^2

60 = 1/2 * a * t^2

We also know that the first traject goes from 0 to 60 m and from 60 to 180 m and finally from 180 to 210 m.
Writing down a couple of equations is not a valid attempt at solution. For this problem, you must examine all the parts of the trip in order to determine the constant speed of the train.
 
SteamKing said:
Writing down a couple of equations is not a valid attempt at solution. For this problem, you must examine all the parts of the trip in order to determine the constant speed of the train.
Yeah I know but I have no idea on what to do next... I wrote down 3 equations for each part of the traject but after that I have no idea...
 
astrololo said:
Yeah I know but I have no idea on what to do next... I wrote down 3 equations for each part of the traject but after that I have no idea...
You wrote down an equation covering the first part of the trip. Don't you think you should write some additional equations describing the other parts of the same trip?
 

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