Calculating de Broglie Wavelengths of Rb Atom and Electron

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SUMMARY

The de Broglie wavelength of a 10 microKelvin rubidium (Rb) atom is calculated to be 86.4 nanometers using the formula λ = h/p, where p is the momentum derived from the velocity equation V = √(3KT/m). The discussion confirms that this method is applicable for the Rb atom and suggests caution when applying it to photons, as the calculations differ significantly. The temperature of the electron in question is 5000K, which also requires similar calculations for its de Broglie wavelength.

PREREQUISITES
  • Understanding of de Broglie wavelength calculations
  • Familiarity with the concepts of momentum and kinetic energy
  • Knowledge of temperature effects on particle velocity
  • Basic grasp of quantum mechanics principles
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  • Calculate the de Broglie wavelength for a 5000K electron using λ = h/p
  • Explore the implications of temperature on particle behavior in quantum mechanics
  • Study the differences in wavelength calculations for photons versus massive particles
  • Review the principles of momentum and kinetic energy in quantum systems
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Homework Statement


What is the de Broglie wavelength of a 10 microKelvin Rb atom? A 5000K electron?


Homework Equations


\lambda=\frac{h}{p}
V=\sqrt{\frac{3KT}{m}}

The Attempt at a Solution


I used the velocity equation to find the velocity relating to temperature and mass. Then, as p=mv, I calculated the wavelength of the Rb atom to be 86.4nm. I just want to make sure my line of thinking is correct and that I can use a similar process for the electron.

Thanks!
 
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Sounds good to me, just be careful if you're thinking about using that method for photons - you will go wrong!
 

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