Calculating Density from Weight: 341N Object Immersed in Water

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Homework Help Overview

The problem involves calculating the density of an object weighing 341 N in air, which is immersed in water, resulting in a force scale reading of 307 N. The context centers around buoyancy and the relationship between weight, volume, and density.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the buoyant force calculated as the difference in weight readings and explore how to derive the volume of the object from this force. There is a focus on the relationship between mass, volume, and density, with some questioning the initial calculations and assumptions made regarding the volume.

Discussion Status

Participants are actively engaging in clarifying concepts related to buoyancy and density calculations. Some guidance has been provided regarding the need to consider the density of water in the calculations, and there is an ongoing exploration of how to correctly find the volume of the object based on the buoyant force.

Contextual Notes

There is mention of potential confusion regarding unit conversions and the assumption that the density of water is constant, which may affect the calculations. Participants are also addressing the need to look up the density of water for accurate computations.

iamtrojan3
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Homework Statement


An object weighing 341 N in air is immersed in water after being tied to a string connected to a force scale. The scale now reads 307 N. Calculate the density of the object.



Homework Equations


Fb=(density of the surrounding liquid)(V)(g)



The Attempt at a Solution


Fb is difference in the forces, 341N-307N = 34N
v = ((initial weight)-(submerged weight))/9.8 = 3.47
mass = 341N/9.8

So Density = m / v

Density therefore = 10.3kg/m^3

Its wrong, i have no idea why, probably some unit conversion somewhere.

thanks!
 
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The 34N that you found is the buoyant force, i.e. the weight of the displaced water. Can you find the mass of the displaced water and then the volume of the displaced water? This volume is the object's volume.
 
The bouyancy force is B = (Density of liquid)(Volume of the object) * g.

V is not the difference in mass (which is what I think you were trying to do), it's the volume of the object.

So you know B and g, and the density of water is fairly constant so you can solve for the volume.

Density as you said is mass divided by volume, and you correctly found the mass, so you just need to find the volume.
 
Feldoh said:
The bouyancy force is B = (Density of liquid)(Volume of the object) * g.

V is not the difference in mass (which is what I think you were trying to do), it's the volume of the object.

So you know B and g, and the density of water is fairly constant so you can solve for the volume.

Density as you said is mass divided by volume, and you correctly found the mass, so you just need to find the volume.

Isn't that what i did? B = Density * V * g and like you said water is fairly constant, so V = B/g
which is 34N/9.8 = 3.47 which is the volume of the object, right?
So now i can do D = m/v for the density of the object given m of object is 341/9.8.

And i just confused myself, we're ignoring the density of water cause its "fairly constant" right?
 
You need to include the density of the water in your volume calculation.
 
Ok, now ill sound just plain stupid.
How do i find the density of water?
 
You can look it up. Its normally 1000kg per cubic metre.
 
Ahh i see what i did thank you all for the help
 

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