Calculating Density of a Submerged Object at 0°C | Check My Answer

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SUMMARY

The density of an object that is 14% submerged in water at 0°C is calculated using the formula \((\text{density of object}/\text{density of liquid}) \times 100 = \%\text{ submerged}\). Given that the density of water at 0°C is 999.87 kg/m³, the correct calculation leads to a density of approximately 139.98 kg/m³ for the object. A common mistake noted in the discussion is the incorrect division of 14% by 100, which should be done as 0.14 instead of 0.0014. This clarification is crucial for accurate density calculations.

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I believe I have correct answer, but I'd just like to confirm with others...

Question: What is the density of an object that is 14% submerged when floating in water at 0 degrees C?

density of water at 0 degrees C = 999.87, according to my book

So the formula I set up is...

((density of object)/(density of liquid)) x 100 = % submerged

Filling in the blanks...

((density of object)/(999.87)) x 100 = 14%

Divide the 14 by 100...

((density of object)/(999.87)) = .14

Multiply the density of water by .14 ...

(999.87)(.14) = 139.9818 = density of object

Have I solved this correctly? Thanks for looking this over!
 
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Looks OK except you do not multiply the density ratio by 100. You multiply by 100% = 100/100 = 1. When you divide 14% by 100 you get .0014. That is not what you did (fortunately). You divided 14% by 100% and got .14
 

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