- #1
vinamas
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Homework Statement
A layer of oil that has a density of 930kg/m^3 is floating on the surface of water in a container if a wooden cube with a length of 4 cm becomes submerged where it's lower half is in water and it's upper half is in oil
the cube's density is 960kg/m^3 find
A) the buoyancy force affecting the cube
B) the length of the cube that is submerged in water
Homework Equations
density=m/v
buoyancy=density*volume*gravity
cubic volume=L^3
The Attempt at a Solution
so I know the cube's density is less than water so it floats
so I use FB=Fg. 960=m/0.04^3. m=0.06144
FB = 0.06144*9.81=0.6027N is that correct?
B)FB=Fg
1000*Vsubmegred*9.81=0.6027
V=0.000061m^3
0.04*0.04*L=V
L=0.038 now this is my problem the answer sheet says that the submerged part's length is 1.71*10^-2
I can't seem to find the significance of oil and it's density what am I doing wrong?