Calculating Density of Gaseous Ethane at 30°C and 771 mmHg | Ideal Gas Laws

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SUMMARY

The density of gaseous ethane (C2H6) at 30°C and 771 mmHg is calculated using the ideal gas law formula: Density = MP/RT. The molar mass (M) of ethane is determined to be 38.048 g/mol. The temperature (T) is converted to Kelvin as 303.15 K, and the pressure (P) is converted to atmospheres as 1.014 atm. Using the ideal gas constant (R) of 0.0821 atm·L/mol·K, the final density is calculated to be 1.54 g/L.

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Homework Statement


Assuming ideal gas behaviour, what would be the density of gaseous ethane (C2H6) at 30. °C and 771 mmHg?


Homework Equations



Ideal gas laws.
I'm using:
Density = MP/RT (M is g/mol)

The Attempt at a Solution



This is one of the questions due online by Sunday night. They're marked by the computer, and we get only a limited number of tries. Anyway, this is my answer and how I arrived at it:

-- M = 2*16+6*1.008 = 38.048 g/mol
-- T = 30 + 273.15 = 303.15 K
-- P = 771/760 = 1.014 atm
-- R = 0.0821 atm*L/mol*K
=> d = MP/RT = (38.048*1.014)/(0.0821*303.15) = 38.43/24.88 = 1.54 g/L

I've tried rounding to 2 digits, to 3 digits... every possible combination. I've gone over the numbers a bazillion times and it keep telling me I'm wrong, and I have 1 try left. What am I doing wrong?
 
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zomg. neevermind. C = 16 ?? glah . this is the sort of stupid mistake that ends up costing me the A.

no soup for me.
 

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