Calculating Distance and Velocity in Two-Dimensional Kinematics

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goj2
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Ive been trying to get this problem. I already have the answers but I want to know how to solve it.

An airplane with a speed of 77.5 m/s is climbing upward at an angle of 34.1 ° with respect to the horizontal. When the plane's altitude is 585 m, the pilot releases a package. (a) Calculate the distance along the ground, measured from a point directly beneath the point of release, to where the package hits the earth. (b) Relative to the ground, determine the angle of the velocity vector of the package just before impact.

The answers are:
(a)1040 m
(b)-61.0°

Can someone help me?
 
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what have you done so far??
 
goj2: a) work out how long the package will take to fall 585m. Then multiply the answer by the forward speed of the aircraft, worked out using trigonometry. b) is more trigonometry based on the forward speed and the vertical speed.