Calculating Distance for Negative Acceleration

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SUMMARY

The discussion focuses on calculating the distance an object travels under negative acceleration until it comes to a stop. The relevant equations include v = u + at, s = ut + 0.5at², and v² - u² = 2as. The user attempted to apply the formula s = -u²/2a but encountered issues with the object not stopping at the calculated distance. The solution involves first determining the time to stop using the equation v = 0 and then substituting that time into the distance equation s = ut + 0.5at².

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Homework Statement



Suppose an object has a velocity v and an acceleration of a, where a is negative. The object will eventually reach a velocity of zero v = 0. How much distance will the object travel until v = 0?

Homework Equations



v = u + at
s = 0.5(u+v)t
s = ut + 0.5 at2
v2 - u2 = 2as

The Attempt at a Solution



Since v2 - u2 = 2as, s = -u2/2a. I implemented this formula into a program I am using, but the object did not stop at the given distance. Am I doing something obviously wrong here? Any help would be greatly appreciated.
 
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Well, using equation 1, set v = 0 and solve for t. Then plug that value into equation 3.
 

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