Calculating Distance Given Work and Forces

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SUMMARY

The discussion revolves around calculating the distance a hay wagon travels given the work done and opposing forces. The farmhand performs 972 J of work while pulling the wagon with a force of 310 N at an angle of 23 degrees below the horizontal, against a frictional force of 280 N. The correct distance traveled is 3.4 m, derived from the net force acting on the wagon, which accounts for friction. The misunderstanding arose from incorrectly using the work done by the farmhand instead of the net work.

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Homework Statement



A farmhand does 972 J of work pulling an empty hay wagon along level ground with a force of 310 N [23 degrees below the horizontal]. A frictional force of 280 N opposes the motion. The distance the wagon travels is
a. 0.39 m
b. 1.7 m
c. 3.4 m
d. 32 m
e. 1.8 x 102 m

Homework Equations



W=FcosΘd
Fnet=F1+F2

The Attempt at a Solution



W=Fd
d=W/F
d=972/(310cos23-280)
d=180 m

Apparently, the correct answer is c) 3.4 m, which works if you don't account friction, but I don't understand how that's correct.
 
Last edited:
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Natko said:

Homework Statement



A farmhand does 972 J of work pulling an empty hay wagon along level ground with a force of 310 N [23 degrees below the horizontal]. A frictional force of 280 N opposes the motion. The distance the wagon travels is
a. 0.39 m
b. 1.7 m
c. 3.4 m
d. 32 m
e. 1.8 x 102 m

Homework Equations



W=FcosΘd
Fnet=F1+F2

The Attempt at a Solution



W=Fd
d=W/F
d=972/(310cos23-280)
d=180 m

Apparently, the correct answer is c) 3.4 m, which works if you don't account friction, but I don't understand how that's correct.

You have divided the work done by the farmhand by the net force . If you are going to use the net force, you need to use the net work, not the work done by the farmhand.
 
I was wrong
 
Last edited:

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