- #1

Lori

## Homework Statement

A sled of mass m is given a kick on a frozen pond. The kick imparts to it an initial speed of 2.20 m/s. The coefficient of kinetic friction between sled and ice is 0.150. Use energy considerations to find the distance the sled moves before it stops

## Homework Equations

Friction Force = Friction coefficient * Normal Force

Normal Force = mass * g

W = KE = 1/2mv^2

W=fd

## The Attempt at a Solution

So, I understand that force of friction is equal to mg*Friction coefficient (given that N=mg)

But, why is mgu=.5mv^2 (final Kinetic )

Shouldn't it be that the work is work done by applied force minus work done by Friction?

Why only look at friction work?