Calculating Distance, Speed, and Displacement in a Skidding Car

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SUMMARY

In the discussion, participants analyze the motion of Julio's truck, which travels north for 20 minutes at 65 mph, west for 15 minutes at 50 mph, and finally north for 5 minutes at 30 mph before breaking down. The total distance traveled is calculated using the formula for distance, while displacement is determined by vector addition of the individual segments. Average speed is computed based on total distance and total time. Additionally, the discussion addresses the skidding phase, where the truck decelerates to a stop over 10 seconds, requiring the application of kinematic equations to find the distance traveled during this deceleration.

PREREQUISITES
  • Understanding of kinematic equations for motion analysis
  • Knowledge of vector addition for calculating displacement
  • Familiarity with average speed calculations
  • Concept of constant acceleration and deceleration in physics
NEXT STEPS
  • Study kinematic equations for uniformly accelerated motion
  • Learn about vector addition and its application in physics
  • Research average speed and its calculation methods
  • Explore real-world applications of motion analysis in automotive engineering
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Students studying physics, automotive engineers, and anyone interested in understanding motion dynamics and calculations related to distance, speed, and displacement.

layaya
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1. julios truck drives north for 20 minutes at 65mph, west for 15 minutes at 50mph, and a final 5 minutes north at 30mph before it breaks down a) what is the total didtance he travled b)what is the magnitude and direction of his displacement c)what was his average speed in mi/h d) when the engine stopped his car skidded decelerating at a constant rate until it came to a complete stop 10 seconds later. how much farther did it travel after losing power?



2.i don't know



3. i don't know
 
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What do you know then, please tell me...

If you have no idea, please read your some pages in your textbook



We always like helping people who show a little effort.


a) what do you know about distance traveled, speed and time?

b) what's the difference between distance and displacement?

c) how do you find average speed when you know displacement and time?


d) You know the speed at the moment the engine breaks down, this will be initial velocity in the "skidding movement", what is the car's speed when it is stopped (the same as you have when sitting in front of the TV), you have the time. First use a certain formula involving the three known and acceleration, then find displacement here by another formula, displacement given by the four variables you know have.

If you're willing to show that you want to do this yourselves, I'll be glad to help you along.


layaya said:
1. julios truck drives north for 20 minutes at 65mph, west for 15 minutes at 50mph, and a final 5 minutes north at 30mph before it breaks down a) what is the total didtance he travled b)what is the magnitude and direction of his displacement c)what was his average speed in mi/h d) when the engine stopped his car skidded decelerating at a constant rate until it came to a complete stop 10 seconds later. how much farther did it travel after losing power?



2.i don't know



3. i don't know
 

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