Calculating Car Accident Speed: 100ft skid marks, 0.75g deceleration

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Homework Help Overview

The discussion revolves around calculating the initial speed of a car involved in an accident, based on the length of skid marks and the deceleration experienced. The subject area includes kinematics and motion equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to identify the correct kinematic equations to relate displacement, acceleration, and initial velocity. Some express confusion about the necessity of solving for time, while others suggest focusing on the variables provided.

Discussion Status

There is an ongoing exploration of the appropriate equations to use, with some participants providing guidance on identifying the relevant kinematic equations. A participant has shared their calculations, indicating a potential direction in the discussion.

Contextual Notes

Participants mention a lack of clarity in instruction and express varying levels of confidence in their understanding of the problem setup and the equations involved.

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Homework Statement



Investigating the scene of a car accident you measure the skid marks of one of the cars to be 100.0ft long. Assuming that the maximum deceleration on dry pavement is 0.75g, what was the minimum speed of the car(in mph) when it slammed on the brakes?

Homework Equations



x=x0 + v0t +1/2at^2
v=v0 + at

The Attempt at a Solution



I know I need to solve for t, but I can't seem to wrap my ahead around setting up the equations for these types of problems. A helpful nudge would be appreciated.
 
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You don't need to solve for time, you are asked to solve initial velocity. You are given 3 values, displacement, acceleration, and final velocity.
 
I was under the impression that most of these problems begin with solving for time. I'm really in the dark on this stuff. My instructor leaves much to be desired.
 
Have you been taught all of the basic kinematic equations?

If so, look at each of them. You'll find that each one has a different variable missing.

Knowing this all you have to do is look for the equation with all the variables you're given and the variable you need and then use that.
 
This is what I did...let me know if I'm on the right track.

I used vf2 + v02 = 2as.

so v02 = 2(7.35m/s2)(30.48m)
v0 = 21.2m/s

I think that's right, but I'm not sure. Then of course I have to convert to mph. Am I close?
 
Yes, that is correct.
 

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