Calculating Distance Traveled for Two Skaters

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SUMMARY

The discussion centers on calculating the distance traveled by two skaters with masses of 9.2 kg and 3.0 kg, who are initially 8.7 m apart and pulling themselves along a rope. The correct approach involves using the concept of the center of mass to determine the distance traveled by the heavier skater. The calculated distance for the 9.2 kg skater is 2.13 m before they meet the other skater, confirming the accuracy of the method applied.

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Two skaters of mass 9.2 kg and mass 3.0 kg stand 8.7 m apart, each holding the end of a rope stretched between them. If each skater pulls himself along the rope until they both meet how far (in m) has the person with the mass of 9.2 kg travel before stopping. Assume that friction is negligible. (Hint: make the 9.2 kg skater your zero reference point and find the center of mass)

X=2.13m?

I don't have time to type my work right now. But will show work if answer is wrong to see where i went wrong.
 
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