Calculating Electric Field: Gauss's Law with Uniformly Distributed Charge

  • Thread starter Thread starter Soulis
  • Start date Start date
  • Tags Tags
    Gauss's law Law
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 2K views
Soulis
Messages
1
Reaction score
0

Homework Statement


A charge of 9 pC is uniformly distributed
throughout the volume between concentric
spherical surfaces having radii of 1.8 cm and
3.8 cm.

Let: Ke = 8.98755 × 109 N · m2/C2 .
What is the magnitude of the electric field
2.9 cm from the center of the surfaces?
Answer in units of N/C

Homework Equations


Electric Flux: (Ie) = E*A = q/epsilon
Electric Field: E = Ke*q/r^2

where A = Surface Area of gaussian sphere, and epsilon is a constant = 8.8542e-12

The Attempt at a Solution


My approach to this problem was assuming their was an inner charge at the center, which I labeled q. To start I used the formula for net flux Ie (electric flux) = E*A = q/epsilon. I neglected the outer sphere completely and used the principle that E (the electric field) is the electric field just outside the conductor and let that equal the charge given in the problem, and epsilon is a constant equal to 8.8542e-12, and A is the surface area of the inner sphere of radius .018m.

E = 9 pC (9e-12)
A = 4pi*r^2 = .004071504079
q = ?
epsilon = 8.8542e-12

Solved for q (my theoretical inner charge)

I used this equation to find my theoretical inner charge of the inner sphere (q) and then applied the generic formula for an electric field at a point P created by a charge q, E = Ke*q/r^2 to solve for the Electric field at P(a distance r from q).

Ke = 8.98755e+9
q = 3.244492027e-25 (answer from first part)
r = .029m

Using this approach I came out with E=3.467304913e-12, which needless to say, was incorrect. I feel I may have overcomplicated this problem and am approaching it incorrectly. Any help would be greatly appreciated, thanks.
 
Physics news on Phys.org