Calculating Energy Needed to Melt an Ice Cube

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Homework Help Overview

The original poster is attempting to calculate the energy required to completely melt an ice cube with a specified mass and initial temperature. The problem involves concepts from thermodynamics, specifically related to heat transfer and phase changes.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the specific heat equation and the need to account for the latent heat of fusion. There is an exploration of the steps involved in calculating the total energy required for both heating the ice and melting it.

Discussion Status

Some participants have provided guidance on the necessary calculations, noting that the original poster had initially overlooked the latent heat aspect of the problem. The discussion reflects a progression towards a more complete understanding of the energy calculations involved.

Contextual Notes

The original poster expresses uncertainty about their initial calculations and the approach needed to arrive at the correct answer. There is an acknowledgment of the importance of considering both the heating of the ice and the phase change to water.

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Homework Statement


How much energy is necessary to completely melt an ice cube of mass 360.6grams that is initially at a temp of -25.2 degrees celsius.


Homework Equations


im thinkin i should use specific heat equation? is that right?
c=Q/m(change of temp)
2090=Q/.36069(25.2)

The Attempt at a Solution


Q= 18992
i kno its wrong but I am not sure what approach i need to take in finding the correct answer.

the correct answer is 1.40x10^5
 
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anyone? help please?
 
You've done one part of the calculation. You've found the energy it takes to heat the ice from -25.2C to 0C, but it's still ice at 0C. You now need to convert this ice into water. How much energy does it take to do that?

Look up the what the term 'Latent Heat' means.
 
ahhh ok.. i knew i missed sumthin important

so ... .3606x25.2x2090= 18992.0808
then i use the latent heat of fusion for water and get .3606x(33.5x10^5)=120801

combine them 18992.0808+120801= 139793.0808 --> 1.4x10^5

thank you gokul
 

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