Calculating Energy of a 701nm Photon

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SUMMARY

The energy of a photon emitted by an excited atom with a wavelength of 701 nm is calculated using the formula E = hc/λ, where h is Planck's constant (6.626e-34 J·s) and c is the speed of light (2.998e8 m/s). After converting the wavelength to meters (701 nm = 701e-9 m), the energy is computed as 2.83e-19 J. However, since the photon is emitted, the final energy value must be expressed as -2.84e-19 J to reflect the emission process. Correct unit notation is crucial in these calculations.

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Homework Statement



An excited atom emits a photon of red light with a wavelength of 701. nm, what is the energy of the photon?----> _________________J


Homework Equations



and for this, my application was

firstly get landa from formula of c=landa * nu

and then landa * h, which is Planck's constant which is 6.626e-34.

since my wavelength is 701 nm, it can be 701e-9 in order to change to meter format.

so my final application would be {(2.998e8m/s)/(701e-9m)} * ( 6.626e-34J*s)= 2.83e-19 (after rounding up to get significant figures which is 3 digits from 701nm)



The Attempt at a Solution



2.83e-19
 
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1. Units! 2.83e-19 even if it's correct numerically is still wrong. You *need* to always have units.

2. Stay in symbols! Write down E = \frac{hc}{\lambda}, then just substitute in the numbers, after conversion to correct units.

(Btw, it's "lambda" not "landa")
 
i did put J (unit) at the end as well and it kept telling me wrong. did i do any conversion wrong?
 
oh, i got it.
the answer needed to be negetive because the question says "emits". so answer had to be negative. i replaced the answer with -2.84e-19 and it was correct. thank you for the help. now i can go to bed.
 

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