Turkish
- 33
- 0
I have a question which I must do yet I can't manage to solve it, any help will be appreciated.
It would be theoretically possible for calcium to forma fluoride CaF containing Ca+ ions and the F- ions in equal numbers. Assuming that the lattice enthalpy of the hypothetical compound is similar to that of NaF (+891 kJ mol ^ -1 ), use a Born-Haber cycle to calculate its enthalpy of formation using the data below
Data:
Enthalpy of atomisation of Ca : +193 kJ Mol ^ -1
F-F Bond enthalpy : +158 kJ Mol ^ -1
First Ionisation Energy of Ca: + 590 kJ Mol ^ -1
Electron Affinity of Flourine: -348 kJ Mol ^ -1
The enthalpy of formation of CaF2 is -1214 kJ mol ^ -1. Use this to explain why it is not possible to produce CaF even if two moles of calcium are reacted with one mole of flourine gas.
It would be theoretically possible for calcium to forma fluoride CaF containing Ca+ ions and the F- ions in equal numbers. Assuming that the lattice enthalpy of the hypothetical compound is similar to that of NaF (+891 kJ mol ^ -1 ), use a Born-Haber cycle to calculate its enthalpy of formation using the data below
Data:
Enthalpy of atomisation of Ca : +193 kJ Mol ^ -1
F-F Bond enthalpy : +158 kJ Mol ^ -1
First Ionisation Energy of Ca: + 590 kJ Mol ^ -1
Electron Affinity of Flourine: -348 kJ Mol ^ -1
The enthalpy of formation of CaF2 is -1214 kJ mol ^ -1. Use this to explain why it is not possible to produce CaF even if two moles of calcium are reacted with one mole of flourine gas.