Calculating Forces in x-y Plane on 5.60 kg Mass

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SUMMARY

The discussion focuses on calculating the resultant force and acceleration of a 5.60 kg mass subjected to three forces: 9.90 N at 17°, 7.40 N at 167°, and 3.80 N at 208°. The participant successfully calculated the x and y components of the forces, yielding -1.1 for the x component and 2.77 for the y component. The angle derived from these components was -68.3 degrees, which was then converted to 291.7 degrees from the positive x-axis. The participant expressed confusion regarding the correctness of this angle in the LONCAPA system.

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  • Familiarity with angle measurement conventions in physics
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Homework Statement



Three forces in the x-y plane act on a 5.60 kg mass: 9.90 N directed at 17o, 7.40 N directed at 167o, and 3.80 N directed at 208o. All angles are measured from the positive x-axis, with positive angles in the Counter-Clockwise direction. Calculate the magnitude of the acceleration. Calculate the direction of the resultant force using the same sign convention as above (in degrees).

Homework Equations


*I do not have problem with the magnitude of acceleration, just the angle!*

tan 0 = y/x

The Attempt at a Solution



x component results in - 1.1
y component results in 2.77

the angle has to be expressed from the positive x axis, when i solve tan inverse(2.77/-1.1)
I get -68.3 degrees, therefore from positive x-axis it equals 291.7 degrees. The LONCAPA (an internet homework place, marks my answer incorrectly). Did I do something wrong?
 
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tan (angle)=tan(angle+180º)
 
PhaseShifter said:
tan (angle)=tan(angle+180º)

thats it! Thank you :D
 

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