Calculating Fragment Numbers: Biotechnology and Plasmids Explained

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    Biotechnology
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Discussion Overview

The discussion focuses on calculating the number of DNA fragments produced when a linear piece of DNA is digested with a restriction enzyme that recognizes a seven-base-pair site. The scope includes mathematical reasoning and conceptual clarification regarding the mechanics of DNA digestion by restriction enzymes.

Discussion Character

  • Mathematical reasoning
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant calculates the number of fragments by dividing the total base pairs by the recognition site length, resulting in a non-integer value, which raises a question about the calculation method.
  • Another participant clarifies that a restriction enzyme cuts at specific recognition sites rather than every seven base pairs, suggesting a misunderstanding in the initial calculation.
  • A third participant points out that the total number of recognition sites on the DNA is unknown, which complicates the prediction of fragment numbers.
  • One participant proposes an alternative calculation using the total number of possible seven-base-pair combinations (4^7) to estimate the number of fragments, resulting in approximately 9 fragments.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the method for calculating the number of fragments, and multiple competing views regarding the approach remain unresolved.

Contextual Notes

The discussion highlights limitations such as the unknown number of recognition sites and the assumptions made in the calculations, which depend on specific definitions of how restriction enzymes operate.

LadiesMan
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A piece of linear DNA is 150 000 base pairs in length and it is digested with a restriction enzyme that recognizes a seven-base-pair recognition site. How many fragments do you predict would be produced? Show your calculations.

I would say, 150000bp / 7 = 21428.57 fragments (Weird...)

What am I doing wrong?

Thanks
 
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A restriction enzyme cuts the DNA at the recognition site. Not every seven base pairs.
 
Hmm, but we don't know how many restriction enzymes are on that linear piece of DNA.
 
maybe:

4 nitrogenous pairs each base pair so 4^7 = 16384 (base pairs) then 150000 divide by 16384 which gives us 9.15 so approximately 9 fragments.
 

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