Calculating Friction Force from Velocity Equation

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To calculate the friction force acting on a 12 kg box that slides to a stop from an initial velocity of +8.4 m/s over a distance of +13.8 m, the acceleration was determined using the equation v^2 = v(o)^2 + 2ad, resulting in an acceleration of -2.55 m/s². This value was then used in the formula F = ma to find the frictional force, leading to a calculation of F = 877(-2.55), which was incorrectly based on an erroneous mass of 877 kg. Upon realizing the correct mass is 12 kg, the calculation was corrected, indicating that frictional force is indeed negative as it opposes the direction of motion. The discussion highlights the importance of careful verification in problem-solving.
mrphobio
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Homework Statement


A 12 kg box slides across the floor with an initial velocity of +8.4 m/s. It comes to a stop after sliding +13.8 m.

How much friction was present?


Homework Equations


f=ma v^2=v(o)^2+2ad


The Attempt at a Solution


I did the ''v^2" equation to find out what the acceleration was, so i could find out what F equaled in f=ma. I got -2.55=a. I plugged that into F=ma, F=877(-2.55), which then F=-2242.06. But can a force be negative? And also from there I'm completely lost.
 
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Frictional force will be negative if you choose the displacement as positive because it is acting opposite to the direction of motion.

Check your math. Where did you get 877 for the mass?? It says 12kg.
 
Well. There we go it worked. I have not a clue where I got that 877. Sometimes another pair of eyes helps a lot haha
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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