- #1
nineteen
- 68
- 12
- Homework Statement
- The statement will be included in the photo I insert.
- Relevant Equations
- F = ma
v^2 = u^2 + 2as
I tried to solve this problem and this is what I could come through:
When the object is moving, the force acting on object is the frictional force, so, it got to be μmg.
So, F = ma and as F is μmg
μmg = ma
μg = a
So, to find out the magnitude of the initial velocity v given to the smaller object, we can substitute the values in the motion equation v2 = u2 + 2as ------> v is final velocity here and u is initial velocity
and this is what we get : v = √2μgL --------------- 1 > v here is the initial velocity of the object as cited in the problem.
Then I went on to find the moment acting on the strip at the toppling instance.
MgXo = mg(L/2 - Xo)
MXo = m(L/2 - Xo) ------------------------ 2
When I combined the equations 1 and 2 and subjected v, I got something like this :
√2μg(MXo/m + 2Xo) = v
But the answer I got is nowhere to be seen in the options list of the multiple choice question. Can you guys please help me? Pleeeeeaaaaaasssseeee guide me...