Calculating Gas Disturbance from a Supernova Explosion

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SUMMARY

The discussion focuses on calculating the mass of gas disturbed by a supernova explosion with an energy output of 1044 J in interstellar matter with a density of 106 m−3 and pressure of 3 x 10−14 N m−2. The analysis indicates that during the snowplough phase, using the snowplough equations with an initial velocity (V0) of 250 km s−1 and an initial radius (R0) of 7 x 1017 m, results in a time (t) of 1.7 x 1014 s, a radius (R) of 2.8 x 1018 m, and a mass affected (M) of 105 M.

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snowmonkey12
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hi guys many thanks in advance for any help, I am revising for an exam and got stuck on this question:

"A supernova of energy 10^44 J explodes in interstellar matter of density n0 = 10^6
m^−3 and pressure Pi = 3*10^−14 N m^−2. Estimate how much gas (mass) can
be disturbed by this supernova. The expansion happens at a velocity Vs = 4 km s^−1."

The answer sheet says the following:

"This is in the snowplough phase. Using the snowplough equations with V0 = 250 km s−1 and R0 = 7*10^17 m gives a time t = 1.7*10^14 s, radius R = 2.8*10^18 m and a mass affected M = 10^5 M⊙."

So basically i have no idea what equation/equations have been used or where the values for the variables. thanks again
 
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