Calculating Gravitational Force Between a Doctor and a Baby

  • Thread starter Thread starter Rasine
  • Start date Start date
  • Tags Tags
    Field
Click For Summary

Homework Help Overview

The discussion revolves around calculating the gravitational force between a doctor and a baby, specifically using the gravitational force formula. The context includes a comparison of gravitational influences from celestial bodies versus those from nearby objects.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the gravitational force formula and question the correct distance to use in the calculation. There is confusion regarding the radius in the formula and its relation to the distance between the centers of the two masses.

Discussion Status

Some participants have offered guidance on correcting the distance used in the calculation. There is an ongoing exploration of the assumptions regarding the radius and the nature of the distance in the gravitational force equation.

Contextual Notes

Participants are navigating the distinction between the distance used in the formula and common interpretations of distance in other contexts. There is a humorous remark about the physical setup, but it does not contribute to resolving the calculation issue.

Rasine
Messages
208
Reaction score
0
Some believe that the positions of the planets at the time of birth influence the newborn. Others deride this and say that the gravitational force exerted on a baby by the obstetrician is greater than that exerted by the planets. To check this claim, first calculate the gravitational force exerted on a 5.7 kg baby by a 87.9 kg doctor who is 1.0 m away.


ok so i am going to use the formula F=G(m1m2)/r^2 and that would be

F=6.67x10^-11(87.9*5.7)/.5^2 which yeilds 1.32 x10^-7 N which is not the right answer

what am i doing wrong
 
Physics news on Phys.org
You have 0.5 for your distance. It should be the 1 m. It is the total distance between the objects you need here.
 
time to call in a replacement--seriously if the center of gravity between the doc and the mom is a meter, those are long forceps. just a joking aside.
 
the equation calls for the radius squared and so i was using .5^2
 
Rasine said:
the equation calls for the radius squared and so i was using .5^2
I think the radius is the distance between the two objects centers. This is different than how we usu think of circles and distance.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
11K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
21K