Calculating Gravity on the Surface of Asteroid Ceres | Forces Homework Help

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SUMMARY

The discussion focuses on calculating the gravitational acceleration on the surface of the asteroid Ceres, which has a mass of 7x1020 kg and a radius of 500 km. The gravitational force equation, Fg = (Gm1m2)/r2, is utilized alongside the weight equation, W = mg, to derive the gravitational acceleration (g). The correct approach involves substituting the known values into the equations to find that the gravitational acceleration on Ceres is approximately 2.24x1021 N. Additionally, an 85 kg astronaut would weigh significantly less on Ceres than on Earth due to this lower gravitational force.

PREREQUISITES
  • Understanding of gravitational force equations, specifically Fg = (Gm1m2)/r2
  • Familiarity with the concept of weight as W = mg
  • Basic knowledge of the gravitational constant, G = 6.67x10-11 N(m/kg)2
  • Ability to perform calculations involving scientific notation
NEXT STEPS
  • Research the gravitational constant and its significance in astrophysics
  • Learn how to calculate gravitational forces on other celestial bodies
  • Explore the implications of low gravity environments on human physiology
  • Study the differences in weight calculations between Earth and other celestial bodies
USEFUL FOR

Students studying physics, particularly those focusing on gravitational forces, as well as educators and anyone interested in the physical properties of celestial bodies like asteroids.

7m-84
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Homework Statement



The asteroid Ceres has a mass of 7x10^20 and a radius of 500km

a. what is the gravity on the surface
b. How much would a 85kg astronaut weigh in ceres

Homework Equations



Fg = (Gm1m2)/r^2

The Attempt at a Solution



None, where do I get the seccond mass value from? or am I using the wrong equation?

pls help, all constructive input appreciated :)
 
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Well, you can use that equation, but you'll need another one: F = mg. You might have seen this before with w (for "weight") in place of F, but it's the same thing. Part (a) is just asking for the value of g, the gravitational acceleration.

Can you see how to put this equation together with the one you have to find g?
 
So something like

w=mg
w=(7.20x10^20)(6.67x10^-11)
w=4.669x10^10

then

fg=(Gm1m2)/r^2
fg=(6.67x10^-11)(4.669x10^10)(7.20x10^20)/500^2
fg=2.24x10^21

like that?
 
In figuring gravity for Ceres, the mass of the object that you want to determine the value of gravity for drops out.

W = m*g = G*M*m/r2

g = G*M/r2

To find W then

W = m*g
 
7m-84 said:
So something like

w=mg
w=(7.20x10^20)(6.67x10^-11)
w=4.669x10^10

then

fg=(Gm1m2)/r^2
fg=(6.67x10^-11)(4.669x10^10)(7.20x10^20)/500^2
fg=2.24x10^21

like that?
No, not that... putting equations together is not the same thing as plugging in numbers. I was trying to point you towards the answer LowlyPion wrote out.
 
got it
 

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