Calculating HCl Concentration in Dilution Problem

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SUMMARY

The discussion centers on calculating the volume of 2M HCl required to dilute 5 liters of 6M HCl to achieve a final concentration of 3.5M. The equation m1v1 = m2v2 is referenced but deemed inadequate for this specific scenario. The correct approach involves determining the total moles of HCl in the final solution, expressed as 2V + 30 (from 6M HCl), and setting this equal to the target concentration of 3.5M in a total volume of V + 5 liters. The solution requires solving the equation 2V + 30 = 3.5(V + 5).

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Homework Statement


How much 2M HCl do you have to add to 5 liters of 6 M HCl, to obtain a 3.5 M HCl solution?

The Attempt at a Solution


I initially thought of something like m1v1=m2v2, but that doesn't seem to really work in this case :/?
 
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How many moles of HCl do you need in the target solution when finished, and how much volume must it be?

Let V = volume of 2M HCl to add. Final solution volume to make is V+5 liters.
Moles of HCl in final prepared solution are 2*V + 6*5 moles.

Analyze the situation and construct the needed equation and solve.
 

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