Calculating HCl Volume for Na2CO3 Reaction

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    Hcl Stoichiometry
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Discussion Overview

The discussion revolves around calculating the volume of hydrochloric acid (HCl) required to react with sodium carbonate (Na2CO3). Participants explore the interpretation of "volume" in the context of the reaction, considering whether it refers to a molarity (M) or a direct amount of moles, and the implications of these interpretations on the calculation process.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant expresses confusion about the term "volume," questioning if it requires finding the mass of HCl and converting it to volume.
  • Another participant suggests that "3.0 mol" might actually refer to "3.0 M" (molarity) of HCl, implying a solution rather than a gas.
  • Some participants propose checking the density of HCl after determining the stoichiometric constant from the balanced equation and calculating the moles of Na2CO3.
  • There is a suggestion that if HCl is considered a gas, the volume would refer to the gas under standard conditions, although this is contested.
  • One participant asserts that the original poster likely meant "3.0 M HCl," as discussing moles in this context would not align with the question about the volume required for the reaction.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether "volume" refers to a molarity or a direct amount of moles, leading to multiple competing interpretations of the problem.

Contextual Notes

There are unresolved assumptions regarding the state of HCl (gas vs. aqueous solution) and the implications of these assumptions on the calculations needed for the reaction.

Johnny_07
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Calculate the volume of 3.0 mol HCl required to react completely with 10.0g of Na2CO3.

Im confused about the "volume". What do they mean ?
Do I have to find the mass of HCl then convert it into a volume?
 
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Are you sure it is not 3.0 M of HCl?

If it's volume, check out density after finding the stoichiometric constant for the balance equation and finding the mol of sodium bicarbonate.
 
kingdomof said:
If it's volume, check out density after finding the stoichiometric constant for the balance equation and finding the mol of sodium bicarbonate.

If it is M (mol/L) you don't need density.
 
unless you are forgetting that HCl is a gas unless specified otherwise (aqueous solution or sth); so by volume they mean the volume of the required gas under normal/standard conditions
 
But we're pretty sure the OP meant 3.0 M HCl, which does imply a solution, not a gas.

If it were really 3.0 moles as stated, it would be pointless to talk about the amount "required to react completely with 10.0g of Na2CO3".
 

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