Calculating Heat Absorbed When Melting 15g Lead

[Mathys]

1. How much heat is absorbed when 15g of lead at its melting point are converted completely to a liquid at the same temperature?
2. (variables: Q=heat, LHf=latent heat of fusion, m=mass) Q=(LHf)(m)
3. I used the formula and I keep getting 367.5J. The answer I was given states that it is actually about 306J. I really don't understand...

Help would be gladly received

 

[Stonebridge]

Your answer is correct.
I get the same value using L=24.5 kJ/kg and m=0.015kg

 

[Mathys]

I see...then the worksheet publishers must be in error. Thank you; I wasted a lot of time because I didn't want to get such a simple question wrong.