# Is heat absorbed, when volume is increased?

## Homework Statement

Hi! Greetings! This is not really a problem set; I just made the question up to better understand PV diagrams of Carnot cycle.

Suppose you have a gas in a container with a movable piston, but is thermally insulated. If the volume of the gas increases, is heat absorbed by the system (the gas particles) or released by the system into the environment?

## Homework Equations

$dQ = dU + dW$
$dQ = dU + PdV$

## The Attempt at a Solution

Hmm.. What I am thinking is that if the volume expands, the gas particles are less compressed and have more place to move around, so I guess the system should give off heat to the surroundings?

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Oh, I got it. It's thermally insulated, so no heat flow. It's the temperature that should change, and if it is an ideal gas, the volume is proportional with temperature and thus, the temperature should increase. Sorry for asking a silly question.. Haha..

## Homework Statement

Hi! Greetings! This is not really a problem set; I just made the question up to better understand PV diagrams of Carnot cycle.

Suppose you have a gas in a container with a movable piston, but is thermally insulated. If the volume of the gas increases, is heat absorbed by the system (the gas particles) or released by the system into the environment?

## Homework Equations

$dQ = dU + dW$
$dQ = dU + PdV$

## The Attempt at a Solution

Hmm.. What I am thinking is that if the volume expands, the gas particles are less compressed and have more place to move around, so I guess the system should give off heat to the surroundings?
If the container is thermally insulated ,there is no heat exchange between the container and the surroundings

• 1 person
Andrew Mason
Homework Helper
Oh, I got it. It's thermally insulated, so no heat flow. It's the temperature that should change, and if it is an ideal gas, the volume is proportional with temperature and thus, the temperature should increase. Sorry for asking a silly question.. Haha..
How can it increase?

Apply the first law. If PdV>0 and Q = 0 what must happen to U?

AM

• 1 person
How can it increase?

Apply the first law. If PdV>0 and Q = 0 what must happen to U?

AM
I guess the internal energy increases if PdV.

But in Carnot cycle there are two types of processes right? Adiabatic and isothermal. The process described above is adiabatic, so I thought there should be some temperature change.

Ah wait.. When the volume increases, the particles are doing work against the system, so the internal energy will decrease. And temperature also would decrease. Am I right?

physicsjn...

dU = -pdV

Now dV > 0 ,so dU <0 i.e internal energy decreases.

Oh I see.. Thank you very much! :)